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0=2.4x^2+24x+10
We move all terms to the left:
0-(2.4x^2+24x+10)=0
We add all the numbers together, and all the variables
-(2.4x^2+24x+10)=0
We get rid of parentheses
-2.4x^2-24x-10=0
a = -2.4; b = -24; c = -10;
Δ = b2-4ac
Δ = -242-4·(-2.4)·(-10)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{30}}{2*-2.4}=\frac{24-4\sqrt{30}}{-4.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{30}}{2*-2.4}=\frac{24+4\sqrt{30}}{-4.8} $
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